Matematik opg 509 511 521-524
Indholdsfortegnelse |
Opg. 509
Midtpunktstransversal = en linie der går mellem to midtpunkter, i en trekant.
- x = |EC| = |BE| = 4
- y = |BD| = |DA| = 3
- b = |AC| = 6(5/3) = 10
Opg. 511
- |AB| = 800 m
Opg. 521
- Areal = 4*3/2 = 6
- |AB| = (3²+4²)^(1/2) = 5
- |CH| = (6*2)/5 = 2,4
- |AH| = (3²-2,4²)^(1/2) = 1,8
- |HB| = (4²-2,4²)^(1/2) = 3,2
Opg. 522
- H = (24²-23,04²)^(1/2) = 6,72
- |RH| = (7²-6,72²)^(1/2) = 1,96
- |RQ| = (6,72/23,04)*24 = 7
- |RP| = 23,04+1,96 = 25