Matematik opg 538-542
Indholdsfortegnelse |
Opg. 538
- <Babc = 70
- <Aabc = 40
- <Cabc = 70
- <Aabd = 180-40 = 140
- <Dabd = <Babd = (180-140)/2 = 20
- <Cbce = 180-70 = 110
- <Ebce = <Bbce = (180-110)/2 = 35
- <Dbde = <Dabd = 20
- <Bbde = <Babd + <Bbce + <Babc = 20 + 35 + 70 = 125
- <Ebde = <Ebce = 35
Opg. 539
- PQS = 180
- PQ = 72
- <PRQ = (360-(90+90+72)) = 108
- <PSQ = (180-(180-72))/2 = 36
- SQ = (180-72) = 108
- <OQS = <PSQ = 36
- <SQT = <PSQ + 90 = 126
- SPQ = 180 + 72 = 152
Opg. 540
- <Aabc = 36
- <Babc = (180-36)/2 = 72
- <Bbka = 72/2 = 36
(bka er ligbenet derfor er |BK| = |AK|)