Opg 4.16


Indholdsfortegnelse

A

LaTex: P = 25 MW\\ I_{220V} = \frac{P}{220V} = 113,64 kA\\ I_{400kV} = \frac{P}{400kV} = 64,5 A\\

B

LaTex: \rho_{al} = 2,72*10^{-8}\\ R_{ledning} = \rho_{al}\times\frac{10^5}{\pi\times 0,025^2} = 1,385

C

LaTex: P_{220V} = 1,385 \times I_{220V}^2 = 17,886 GW\\ P_{400kV} = 1,385 \times I_{400kV}^2 = 5,41 kW\\

D

LaTex: \frac{5,4kW}{25mW} = 0,216

E

LaTex: \frac{5}{0,21}\times 100 = 2380,9km