Opgave 47-48 og 37-38 kemi


Indholdsfortegnelse

Opg 47

  1. 3,2g/24,30g/mol = 0,132 Mol
  2. 24L/Mol*0,132Mol = 3,17 L

Opg 48

  1. 3Bar*35L/(0,08314L*Bar/(Mol*K)*323,15K) = 3,91 Mol
  2. 3,91mol/3*2*(23+3*14)g/mol = 169.433 g

Opg 37

  • C4H8S = 5,92g = 5,92/(12*4+8*1+32) = 0,067 mol
  • O2 = 0,067mol*7*16*2g/mol = 15 g
  • CO2 = 0,067mol*4*(16*2+12)g/mol = 11,792 g
  • H2O = 0,067mol*4*(1*2+16)g/mol = 4,824 g
  • SO2 = 0,067mol*(32+2*16)g/mol = 4,288 g

Opg 38

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